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maksim [4K]
3 years ago
8

Which is more valuable $20000 received now or $5000 per year for 4 years?

Mathematics
1 answer:
zheka24 [161]3 years ago
7 0
Getting the money now lets you use it now, and if you invest wisely, get more profit. Waiting four years to get it all is an interest free loan.
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Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
2 years ago
A die is rolled find the probability of rolling a multipul of 5​
Pavlova-9 [17]

Answer:

1/6

Step-by-step explanation:

It's 1/6 because the only multiple of 5 in a die is 5, so it will be 1/6.

3 0
3 years ago
Jaime earned some money mowing the neighbor's lawn. He spent one-fourth of his money to take his friends to see a movie. Then he
steposvetlana [31]

The answer is 104.

1/4 of 104 is 26, 104 - 26 = 78

78 - 7 = $71

3 0
3 years ago
Mary got a sales job at her father's company. She was paid $9 per hour plus a 5%commission on her sales. Last week sheworked 40
horsena [70]

Answer:

Mary was paid $638

Step-by-step explanation:

Mary was paid 360 $ for working alone because

$40 * 9 = $360

Mary was paid $278

5 % * $5560 = $278

360 + 278 = 638 $

5 0
2 years ago
What SPC tool best indicates the shape of the data population and indicates if there are any gaps in the data
romanna [79]
The gaps in the area needs to be closed so the data you use is lenient
7 0
1 year ago
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