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2 years ago

Find the value of e in the equation: sin 0 = = -1

Mathematics

1 answer:

julsineya [31]2 years ago

7 0

Answer:

-1

Step-by-step explanation:

its just -1beacuse I did it

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Please solve asap thanks

zubka84 [21]

How do i solve it omg

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2 years ago

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Find dy/dx for (y^2/x) = 18 by implicit differentiation

Natasha2012 [34]

9514 1404 393

Answer:

dy/dx = y/(2x)

Step-by-step explanation:

The product formula can be used, along with the power rule.

d(uv) = du·v +u·dv

d(y^2/x) = d(18)

2y·dy/x -y^2/x^2·dx = 0

2x·dy -y·dx = 0 . . . . . . . . multiply by x^2/y

dy/dx = y/(2x) . . . . . . . . add y·dx, divide by 2x·dx

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2 years ago

What is the least common denominator of 3/4, 4/5, 2/3?

morpeh [17]

D A A C A C A B A D A C B B 1/1/3 B 43/1/5 A A

4 0

2 years ago

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A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

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2 years ago

What is the mean number of people in each age range? Explain

RSB [31]

To find the mean you add all the numbers then divide by how many numbers there are :

8+16+12+11+8=55

in the equation there are 5 numbers, so you divide 55 by 5 :

55÷5=11

the mean is 11

hope this helps

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2 years ago

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