Regulatory or informational markers are utilized to inform you with respect to circumstances, threats, or headings. They may show reefs, swim territories, speed zones, and so forth. They can be effectively distinguished by the orange groups on the top and base of each float.
The option that can be used to identify and analyze which characteristic of OSPF signifies this is known to be Low overhead, fast convergence.
<h3>What is OSPF about?</h3>
The OSPF is known to be called an open Shortest Path First protocol.
It belongs to the family of IP Routing protocols as it serves as Interior Gateway Protocol (IGP) used mainly for the Internet, and the option that can be used to identify and analyze which characteristic of OSPF signifies this is known to be Low overhead, fast convergence.
See full question below
A network administrator has asked Robin, a network engineer, to use OSPF (Open Shortest Path First) along with RIP (Routing Information Protocol) on an edge router in a network so that it demands more memory and CPU power for calculations but keeps network bandwidth to a minimum with a very fast convergence time. Identify and analyze which characteristic of OSPF signifies this.
Shared data
Low overhead, fast convergence
Stability
Multi-vendor routers
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Answer:
Which statement accurately describes his key to success?
Explanation:
The success in Netflix lies in offering:
1. Entertainment;
2. fun;
3. originality;
4. innovation and
5. happiness.
Netflix learning is:
1. Bet on your content.
2. Brand Personality.
3. Visual universe.
4. Customization
5. Big Data helps Netflix continue to grow and improve customer service.
Answer:
Check the explanation
Explanation:
Here is the program with function definition and two sample calls.
Code:
#include <iostream>
using namespace std;
//checkMe FUNCTION which takes values a, b and c
void checkMe(char &a, int &b, int &c)
{
//if sum of b and c is negative and a is 'n', b and c are set to 0, otherwise a is set to 'p'
if((b+c)<0 && a=='n')
{
b = 0;
c = 0;
}
else
{
a = 'p';
}
}
int main()
{
//first test case when else part is executed
char a = 'n';
int b = 5;
int c = 6;
checkMe(a, b, c);
cout<<a<<" "<<b<<" "<<c<<endl;
//second test case when if part is executed
a = 'n';
b = -4;
c = -5;
checkMe(a, b, c);
cout<<a<<" "<<b<<" "<<c<<endl;
return 0;
}
Kindly check the Output below:
