Janelle should have clicked Save & Close to close the contact.
Answer:
Following are the solution to this question:
Explanation:
Some of the data is missing in the question, which is defined in the attached file. Please find it.
Follows are the formula which is used in the question:
- EmployeeAnalysis Worksheet IF(C5>49,"Certified","Not Certified")
- Transactions Worksheet IF(F10="No","",0.07)
In the first condition, it checks "C5" is greater than 49 if the condition is true, it will give "Certified" otherwise, it will give "Not Certified".
In the second condition, it checks "F10" is equal to "No" if the condition is true, it will give a blank or space otherwise, it will give "0.07".
Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
Answer:
are u sure this is the right question?
Explanation:
Answer:
True
Explanation:
They want to focus on their customers and their interests, so they market their products to a specific audience. hope this helps :)
