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alexandr1967 [171]

2 years ago

7

Translate the statements in english where c ( x, y ) means that student x is enrolled in class y, where the domain of x consists

of all students in your school and the domain of y consists of all classes being offered at your school.

1 answer:

Galina-37 [17]2 years ago

6 0

C(x+y) there's your answer ratattoo

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What is the value of 4)1/8 divided by 5)1/2

Over [174]

Answer:

I'm assuming that you meant to type: The question is x/5=1/2+1/8 ; X= ?

If so, we're solving for x.

x/5 = 1/2 + 1/8

2 is a factor of 8, so let's start with common denominators.

x/5 = 1/2 *(4/4) + 1/8

x/5 = 4/8 + 1/8

x/5 = 5/8 As long as we just need to know the value of x, let's use inverse operations.

x/5 *5 = 5/8 *5

x = 25/8 or 3.125

6 0

2 years ago

Joshua borrowed $2,100 for one year and paid $105 in interest. The bank charged him a service charge of $18. If Joshua paid the

fredd [130]

the answer of monthly is 27,213

6 0

3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$

At x = $\frac{-1}{2}$ ,

$f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0$

We know that if $f''(a)>0$ then x = a is a point of minima.

So, $x=\frac{-1}{2}$ is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0

3 years ago

Solve the equation k+10=27 k=

Reil [10]

Steps to solve:

k + 10 = 27

~Subtract 10 to both sides

k = 17

Best of Luck!

8 0

3 years ago

Please help with this geometry question!

faltersainse [42]

Since the properties of a rhombus tells us that both pairs of opposite sides are congruent we can therefore conclude that DB will be 12

6 0

2 years ago