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faust18 [17]
3 years ago
6

Can someone please help me find the mean absolute deviation of these numbers: 15, 17, 15, 17, 21, 23

Mathematics
1 answer:
Igoryamba3 years ago
3 0

Answer:

Step-by-step explanation:

mean absolute deviation=(|x-mean|)/number of terms.

mean=\frac{ 15+17+15+17+21+23}{6}=\frac{108}{6} =18\\x  ~ |x-mean|\\15    ~3\\17     ~ 1\\\\15      ~3\\17    ~1\\21     ~3\\23    ~5\\\sum=16\\mean~absolute~deviation=\frac{16}{6} =\frac{8}{3} =2  \frac{1}{3}

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<h2><u>Answer with explanation:</u></h2>

Let \mu be the population mean strain in a way that conveys information about precision and reliability.

The sample mean is the best point estimate of the true population mean .

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Sample size : n= 12

degree of freedom : df=12-1=11

Sample mean : \overline{x}=25.0

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sample standard deviation : s= 3.3

Significance level : \alpha= 0.05

Since sample population standard deviation is unknown , so we use t-test.

Critical t-value for t : t_{\alpha/2, df}=t_{0.025, 11}=2.201

95% Confidence interval for true average strain in a way that conveys information about precision and reliability:

\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

25.0\pm (2.201)\dfrac{3.3}{\sqrt{12}}\\\\=\approx 25.0\pm2.10\\\\=(25.0-2.10, 25.0+2.10)=(22.9,\ 27.1)

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