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Andreyy89
3 years ago
11

Which equation could be used to solve for the length of XY? XY = (22) sin (41°) XY = (22) cos (41°) XY = Start Fraction 22 Over

cosine (41 degrees) End Fraction XY = Start Fraction 22 Over sine (41 degrees) End Fraction
Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0

Answer:

The answer is D.

Step-by-step explanation:

I just took the test

Solnce55 [7]3 years ago
4 0

Answer:

Pythagorean's theorem: a²+ b²= c²

Sines: sin A = a/c, sin B = b/c.

Cosines: cos A = b/c, cos B = a/c.

Tangents: tan A = a/b, tan B = b/a.

Step-by-step explanation:

For example, if the side a = 22 and the angle A = 41°, we can use a sine and a tangent to find the hypotenuse and the other side. Since sin A = a/c, therefore c = a/sin A = 22/sin 41. Using a calculator, this is 22/0.6561 = 33.5314. Also, tan A = a/b, so b = a/tan A = 22/tan 41 = 22/0.8693 = 25.307.

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alukav5142 [94]

Answer:

the median is 80.5

Step-by-step explanation:

first we put them in order

75,76,77,79,80,81,85,86,90,91

the median is the middle number...however, in cases where there are an even number of numbers, ur gonna have 2 middle numbers....so u take the average of those 2 numbers...basically, u add them and divide by 2.

So we have 2 numbers in the middle.....we add them and divide by 2 to get the median.

(80 + 81) / 2 = 161/2 = 80.5 <== the median

8 0
3 years ago
Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
Debora [2.8K]

So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

\int\limits^1_0 {x^{2} } \, dx = 13

We find

\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

4 0
2 years ago
Aidan is paying his taxes and realizes that he was in the first tax bracket (10%) last year. Eleven years ago, he bought a commo
Makovka662 [10]
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3 0
3 years ago
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vichka [17]

Answer:

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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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