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3 years ago

A box contains 3 items that are labeled a, b, and

Mathematics

1 answer:

Mars2501 [29]3 years ago

7 0

you could pick:

A & B

A & C

B & C

B & A

C & A

C & B

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Solve for x a 2.2 b 5.4 c 6.5 d 7.2

Reika [66]

Answer:

Step-by-step explanation:

Given that the segment is an angle bisector then the ratio of sides and base are equal, that is

$\frac{10}{4}$ = $\frac{18}{x}$ ( cross- multiply )

10x = 72 ( divide both sides by 10 )

x = 7.2 → D

8 0

3 years ago

HELPPPPPPPPPPPP

vlabodo [156]

Answer:

25cm

Step-by-step explanation:

one the possibility 36 - 11 =25 the answer is 25

8 0

2 years ago

The illustration below is of the circle (x + 6)2 + (y + 7)2 = 4. True False

mafiozo [28]

True true true true true

3 0

3 years ago

Read 2 more answers

A bus travels on an east-west highway connecting two cities A and B that are 100 miles apart. There are 2 services stations alon

melamori03 [73]

Answer:

51/4

Step-by-step explanation:

To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.

X~ Uniform(0,100)

Then the probability mass function is given as follows.

$f(x) = P(X=x) = 1/100 \,\,\,\, \text{if} \,\,\,\, 0 \leq x \leq 100\\f(x) = P(X=x) = 0 \,\,\,\, \text{otherwise}$

Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located 70 meters away from city A then the mid point between 20 and 70 is (70+20)/2 = 45 then we can represent D as follows

$D(x) =\left\{ \begin{array}{ll} x & \mbox{if } 0\leq x \leq 20 \\ x-20 & \mbox{if } 20\leq x < 45\\ 70-x & \mbox{if } 45 \leq x \leq 70\\ x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.$

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable $Y = D(X)$ , $Y$ is a random variable as well, remember that there is a theorem that says that

$E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx$

Where $f(x)$ is the probability mass function of X. Using the information of our problem

$E[Y] = \int\limits_{-\infty}^{\infty} D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx \bigg]\\= \frac{51}{4} = 12.75$

3 0

3 years ago

Write the equation for the graph

melamori03 [73]

Answer:

i think its (4, -4) hope that helps u :0

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers