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Ratling [72]
3 years ago
10

A bucket holds 2 gallons of water. If you pour out 1/4 of the water, how many gallons of water do you have left in the blucket?

Mathematics
1 answer:
amid [387]3 years ago
3 0
The answer is 1.75.
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Angle DEB is 42. State the size of angle ABD
Kay [80]

Answer:

The answer would be 80 ° because 5×( 2 + 13 or x +1 ) is 80

Step-by-step explanation:

ABD is 80°

If DEB is 42 °

∠ ABD = 5(2X+1)

∠ DBC = 3X+6

∠ EBC = Y +135/2

∠ ABD and ∠ DBC are linear pairs

∴ ∠ ABD +∠ DBC = 180

∴ 5(2X+1) + 3X+6 =180

solve for x

∴ x = 13

∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135

 ∠ DBC = 3x+6  = 3*13+6 = 45

∠ ABD  and ∠ EBC are vertical angles

∴ ∠ ABD = ∠ EBC = 135

∴ y +135/2 = 135

∴ y = 135/2

5 0
3 years ago
Element X is a radioactive isotope such that every 81 years, its mass decreases by half. Given that the initial mass of a sample
Ksenya-84 [330]

Answer:

1426

Step-by-step explanation:

this question has been asked before and answered incorrectly but people corrected them in the comments.

3 0
2 years ago
Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.
Paladinen [302]

Answer:  a) 1024, b) 1, c) 64 and d) 0.125.

Step-by-step explanation:

Since we have given that

(a) (4^3)(4^2)

As we know that

a^m\times a^n=a^{m+n}

So, it becomes,

4^3\times 4^2=4^{3+2}=4^5=1024

(b) (\dfrac{1}{4})^2(4^2)

As we know that

a^{-m}=\dfrac{1}{a^m}

(\dfrac{1}{4})^2(4^2)=4^-2\times 4^2=4^{-2+2}=4^0=1

c) (4^6)1/2

As we know that

(4^6)^{\frac{1}{2}}\\\\=4^{\frac{6}{2}}\\\\=4^3\\\\=64

(d) [(8^{-1})(8^{\frac{2}{3}})]^3

As we know that

[(8^{-1})(8^{\frac{2}{3}})]^3\\\\=[8^{-1+\frac{2}{3}}]^3\\\\=[8^{\frac{-1}{3}}]^3\\\\=8^{-1}\\\\=\dfrac{1}{8}=0.125

Hence, a) 1024, b) 1, c) 64 and d) 0.125.

5 0
2 years ago
Katherine wants to construct a small box with a volume of 20 cubic inches with the following specifications. The length of a box
pochemuha
V=LWH=20

L is 5 more than W
V=5+W

H is 1 less than W
H=-1+W

easy, sub 5+W for L and -1+W for H in LWH=V=20

20=(5+W)(W)(-1+W)
expand
20=W^3+4W^2-5W
minus 20 both sides
W^3+4W^2-5W-20=0
either factor or graph to find the possible values for W
(W+4)(W^2-5)=0
set each to zero

W+4=0
W=-4
impossible, measures cannot be negative
W^2-5=0
add 5
W^2=5
sqrt both sides
W=√5

sub back

L=5+W
L=5+√5
aprox
7.24 rounded

H=-1+W
H=-1+√5
aprox
1.24 rounded
the dimentions are
√5 by (5+√5) by (-1+√5) or aprox
2.24in by 7.24in by 1.24in
5 0
2 years ago
Read 2 more answers
Complete the circles so that the sum of any three consecutive digits is 10<br><br>2000000010
crimeas [40]
Where are the circles? when asking questions please provide and the information
7 0
2 years ago
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