The equation of line passing through the point P(-8,0) that is perpendicular to the line y=-3 is y=0 which can be found out from slope intercept formula.
It is given to us that -
The point is P(-8,0)
The line is represented as y=-3
The point P is perpendicular to the given line.
We have to find out the equation of the line passing through P which is perpendicular to the given line.
We know that the equation of a line is given by -
y = mx + c
where, (x, y) = coordinates of the point
m = slope of the line
c = a constant
Comparing this with the equation of the given line, we have
m=0 and c =-3
This implies that the slope of the perpendicular is also equal to 0.
The slope intercept formula for the perpendicular line can be represented as -
y = mx + c
Using the coordinates of P(-8,0), we have
0 = 0*(-8) +c
=> c = 0.
Thus, the equation of line passing through the point P(-8,0) that is perpendicular to the line y=-3 is y=0.
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Answer:
option 1 or should be
Step-by-step explanation:
4/1.5 is 2.6 and 2/3 as a fraction is 66666 so yeah
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<h3>Solution:-</h3>
⟹( 4x + 3 )( 2x - 5 )
⟹( 4x × 2x ) - ( 4x × - 5) + ( 3 × 2x )-( 3×-5 )
⟹8x²- ( - 20x ) + 6x - ( - 15 )
⟹8x² + 20x + 6x + 15
<h3>⟹8x² + 26x + 15</h3>