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Softa [21]
3 years ago
12

Solve for u.

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0
Make 5u subject of formula
5u=10+15
5u=25
Didn’t both side by 5
U =5
STALIN [3.7K]3 years ago
5 0

Answer:

5u-15=10 |+15

5u=25 |:5

u=5

The solution is 25

I hope it helps

have anice day

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Answer:

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Answer:

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Minimum = 300 at (0,10) or (12,2).

Step-by-step explanation:

The given linear programming problem is

Minimize and maximize: P = 20x + 30y

Subject to constraint,

2x+3y\ge 30            .... (1)

2x+y\le 26            .... (2)

-2x+3y\le 30            .... (3)

x,y\geq 0

The related equation of given inequalities are

2x+3y=30

2x+y=26

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For inequality (1).

x      y

0     10

15     0

For inequality (2).

x      y

0     26

13     0

For inequality (3).

x      y

0     10

15     0

Pot these ordered pairs on a coordinate plane and connect them draw the corresponding related line.

Check each inequality by (0,0).

2(0)+3(0)\ge 30\Rightarrow 0\ge 30    False

2(0)+(0)\le 26\Rightarrow 0\le 26     True

-2(0)+3(0)\le 30\Rightarrow 0\le 30    True

It means (0,0) is included in the shaded region of inequality (2) and (3), and (0,0) is not included in the shaded region of inequality (1).

From the below graph it is clear that the vertices of feasible region are (0,10), (6,14) and (12,2).

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(0,10)           P = 20(0) + 30(10) = 300

(6,14)           P = 20(6) + 30(14) = 540

(12,2)           P = 20(12) + 30(2) = 300

It means objective function is maximum at (6,14) and minimum at (0,10) or (12,2).

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