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3 years ago

The difference of two numbers is equal to 0.6. Their quotient is also 0.6. What are the numbers? There are 4

1 answer:

8 0

Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
x - y = 0.6
y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
x/y = 0.6 . . . . . . . assuming y has the larger magnitude

The solution of the first pair of equations is
(x, y) = (1.5, 0.9)

The solution of the first and last equations is
(x, y) = (-0.9, -1.5)

The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.

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Yasmin swims at a constant rate of 2 km/h for 2.5 h. How far does Yasmin swim? 4.5 km 5 km 6 km 6.5 km

Neporo4naja [7]

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3 years ago

Is 0.6 less then five eighths

AVprozaik [17]

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3 years ago

Read 2 more answers

2x - y = 8<br> y= x-3<br> Use substitution method

uranmaximum [27]

Answer:

Slope = 0.222/2.000 = 0.111

x-intercept = -3/1 = -3.00000

y-intercept = 3/9 = 1/3 = 0.33333

Step-by-step explanation:

Step 1 :

Equation of a Straight Line

1.1 Solve x-9y+3 = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line x-9y+3 = 0 and calculate its properties

Graph of a Straight Line :

Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 1/3 so this line "cuts" the y axis at y= 0.33333

y-intercept = 3/9 = 1/3 = 0.33333

Calculate the X-Intercept :

When y = 0 the value of x is -3/1 Our line therefore "cuts" the x axis at x=-3.00000

x-intercept = -3/1 = -3.00000

Calculate the Slope :

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 0.333 and for x=2.000, the value of y is 0.556. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 0.556 - 0.333 = 0.222 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

Slope = 0.222/2.000 = 0.111

Geometric figure: Straight Line

Slope = 0.222/2.000 = 0.111

x-intercept = -3/1 = -3.00000

y-intercept = 3/9 = 1/3 = 0.33333

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plz mark me as brainliest if this helped :)

3 0

3 years ago

Answer these below. its for algerbra math

pantera1 [17]

Answer:

lin

Step-by-step explanation:

3 0

3 years ago

A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per

HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0

3 years ago