I think you just add all the sides even the ones you don't see. The left side of the shape is 6m as well as the right. and the same with the 4s. The answer is 36.
Answer:
6.11km/hr
Step-by-step explanation:
Let the speed that Kelli swims be represented by Y
Speed of the river = 5km/hr
Distance = Speed × Time
Kelli swam upstream for some distance in one hour
Swimming upstream takes a negative sign, hence:
1 hour ×( Y - 5) = Distance
Distance = Y - 5
She then swam downstream the same river for the same distance in only 6 minutes
Downstream takes a positive sign
Converting 6 minutes to hour =
60 minutes = 1 hour
6 minutes =
Cross Multiply
6/60 = 1/10 hour
Hence, Distance =
1/10 × (Y + 5)
= Y/10 + 1/2
Equating both equations we have:
Y - 5 = Y/10 + 1/2
Collect like terms
Y - Y/10 = 5 + 1/2
9Y/10 = 5 1/2
9Y/ 10 = 11/2
Cross Multiply
9Y × 2 = 10 × 11
18Y = 110
Y = 110/18
Y = 6.1111111111 km/hr
Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.
DGFH is a rhombus where E is the midpoint of the lines GE and GF
please look at the image
Answer:
<u>32</u>
Step-by-step explanation:
I proceeded to divide the shape up into 2 triangle and 1 square. The added sum of the 2 divided triangles is 16 and the square is 16. Add those to to get <u>32</u>.
The following shape is a trapezoid
area formula:
A=
A=
A= (4)(12+4)
A= (4)(16)
A= (4)(16)
A= (64)
A=32
Also, is that Khan Academy?
The answer would be 102 <span>÷ 34 = 3</span>
