Answer:
The answer is B.
Step-by-step explanation:
1) Area = leg(1) * leg(2) * .5 = 15 * 36 * .5 = 270
Perimeter = leg(1) + leg(2) + hypotenuse = 15 + 36 + 39 = 90
2) Area = leg(1) * leg(2) = 20 * 80 = 1600
3) Median (divides it in 1/2)
4) Both (divides it in 1/2 and makes a 90 degree angle w/ base)
5) Altitude (makes 90 degree angle w/ base)
6)sqrt(30^2 + 16^2) = sqrt( 900 + 256) = sqrt(1156) = 34
7) sqrt(24^2 + 18^2) = sqrt( 576 + 324) = sqrt(900) = 30
8) sqrt(40^2 + 96^2) = sqrt(1600 + 9216) = sqrt(10816) = 104
9) sqrt(150^2 - 90^2) = sqrt(22500 - 8100) = sqrt(14400) = 120
10) sqrt(35^2 - 25^2) = sqrt(1225 - 625) = sqrt(600) = 10sqrt(6), approx. 24.5
The smaller sector is 360-255=105 degree
it is 105/360 portion of the whole circle, and the area of the whole circle is πr², r is 14
so the area of the smaller sector is (105/360)*π*14²
run those numbers through your calculator, use 3.14 for π, you get 179.5
if you are looking for area of the larger sector, it would be
(255/360)*π*14²=435.94
Answer:
6 knots
Step-by-step explanation:
Let the speed be v knots
then time taken to cover 500 M = 500 / v hrs
fuel consumption /hr = 216 + 0.5v^3
let F be the fuel consumption for trip
= [500/v][216 + 0.5v^3]
= 500[216/v + 0.5v^2]
dF/dv = 500[ - 216/v^2 + v]
d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve
so setting dF/dv will give a minima
500[ -216/v^2 + v] = 0
or v = 216/v^2
or v^3 = 216
solving, we get v = [216]^(1/3) = 6 knots
The reflected points are (4, -1) and (-2, 6).
