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Wittaler [7]
3 years ago
7

Joanna ran a mile in physical education class. After resting for one hour, her heart rate was 60 beats per minute. If her heart

rate decreased by 2 over 5 , what was her heart rate immediately after she ran the mile?
Mathematics
1 answer:
umka2103 [35]3 years ago
8 0
<span>Let x be Joanna's heart rate immediately after running one mile. After this heart rate x decreased by 2 over 5, Joanna's heart rate was 60 beats per minute. We can set up an equation to solve this question. x - (2/5) x = 60 (3/5) x = 60 x = (5/3) 60 x = 300 / 3 x = 100 Joanna's heart rate immediately after running one mile was 100 beats per minute.</span>
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Answer:

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Step-by-step explanation:

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2 years ago
write an equation in slope intercept form for the line described. perpendicular to y = -1/2x + 2/3, passes through (2,3)
Alex17521 [72]

Step-by-step explanation:

Hey there!

Follow the steps to get answer.

  • Use one point formula and find 1st equation.
  • After that you find the slope of second equation.
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  • Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

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2nd equation..

Now, From equation (ii)

We have;

Comparing equation (ii) with y = mx+c.

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Slope = -1/2.

For perpendicular lines,

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Put value of slope (m1) in equation (i). We get;

(y - 3) = 2(x - 2)

Simplify them to get equation.

(y - 3) = 2x - 4

y = 2x - 1

Therefore the required equation is y = 2x-1.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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Answer:

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hope it helped

 

Step-by-step explanation:

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