Have an average weight of 16 ounces and a standard deviation of 0.2 ounces. the weights of the sugar bags are normally distribut
ed. what is the probability that 16 randomly selected packages will have a weight in excess of 16.075 ounces?
1 answer:
Standardised z score = (16.075 - 16) / 0.2 = 0.375
which gives a probability of 0.1462 for selecting a package of weight 16.075
the probability of weight being excess of 16.075 = 0.5 - 0.1462 = 03538
Probability of picking 16 in excess of 16-075 = 0.3538^16 = 6.0273 * 10^-8
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mark brainliest please it would help alot
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