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alisha [4.7K]
3 years ago
13

To display measurements on the ruler while changing column widths, hold down the ________ key while dragging the marker.

Computers and Technology
1 answer:
Yuri [45]3 years ago
8 0

Answer:

The correct answer to the following question will be "Alt".

Explanation:

The Alt key is usable on a computer keyboard for monitor calculation adjustments. It is a feature that uses other keys. It's also referred to as a modifier key in a SHIFT key similar.

  • This key used in the office which uses a file menu or display keyboard shortcuts that is available on the ribbon.
  • It switches between the file menu options using the arrow keys until chosen.
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In linear programming a solution that does not simultaneously satisfy all constraints is called an
Eddi Din [679]
<span>When it comes to linear programming, the solution which would be effective in satisfying all constraints in the given program in a simultaneous matter is called that of feasible programming. This is due to the fact that the program can satisfy all requirements at the same time.</span>
3 0
4 years ago
Jessie will make and sell the trending Baked California Maki. Her Peso mark up is 5.00. Selling price PHP 15.000. How much will
Levart [38]

Answer:

50%

Explanation:

The markup is the difference between the selling price and the cost price. If the mark up is greater than zero, it means there is a profit, if the markup is less than 0, it means there is a loss and if the markup is equal to 0, it means there is breakeven.

Percentage markup = (markup/cost price) * 100%

Selling price - cost price = markup

15 - cost price = 5

cost price = 10

Percentage markup = (markup/cost price) * 100% = (5/10) * 100% = 50%

7 0
3 years ago
Write a program that takes three numbers as input from the user, and prints the largest.
S_A_V [24]

Answer:

In Python:

n1 = int(input("Enter a number: "))

n2 = int(input("Enter a number: "))

n3 = int(input("Enter a number: "))

if n1 >= n2 and n1 >= n3:

   print("Largest: "+str(n1))

elif n2 >= n1 and n2 >= n3:

   print("Largest: "+str(n2))

else:

   print("Largest: "+str(n3))

Explanation:

The next three lines get three numbers from the user

n1 = int(input("Enter a number: "))

n2 = int(input("Enter a number: "))

n3 = int(input("Enter a number: "))

This checks if the first number is greater than the other two. If yes, the first number is printed as the largest

<em>if n1 >= n2 and n1 >= n3:</em>

<em>    print("Largest: "+str(n1))</em>

This checks if the second number is greater than the other two. If yes, the second number is printed as the largest

<em>elif n2 >= n1 and n2 >= n3:</em>

<em>    print("Largest: "+str(n2))</em>

This prints the third number as the largest, if the other two conditions fail

else:

   print("Largest: "+str(n3))

3 0
3 years ago
Read 2 more answers
What is the purpose of the Revisions pane in a presentation?
lana [24]
First option


Sorry if I’m wrong
7 0
3 years ago
Read 2 more answers
Given two variables, is Empty of type boolean, indicating whether a class roster is empty or not, and number Of Credits of type
Alex_Xolod [135]

Answer:

     if(isEmpty || numOfCredits==3){

         

     }

Explanation:

Consider a complete java program below that prompts user for  number of credits and also asks if class roster is empty or not

<em>import java.util.Scanner;</em>

<em>public class num13 {</em>

<em>    public static void main(String[] args) {</em>

<em>        boolean isEmpty = false;</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        System.out.println("Is class Rooster Empty? Yes or No");</em>

<em>        String ans = in.next();</em>

<em>        if(ans.equalsIgnoreCase("yes")){</em>

<em>            isEmpty = true;</em>

<em>        }</em>

<em>        else isEmpty =false;</em>

<em>        System.out.println("Enter number of credits");</em>

<em>      int numOfCredits = in.nextInt();</em>

<em>      if(isEmpty||numOfCredits==3){</em>

<em>          System.out.println("True");</em>

<em>      }</em>

<em>      else {</em>

<em>          System.out.println("Not true");</em>

<em>      }</em>

<em>    }</em>

<em>}</em>

4 0
3 years ago
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