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Refer to the exhibit. If a hacker on the outside network sends an IP packet with source address 172.30.1.50, destination address

Luden [163]

Answer:

The packet is dropped

Explanation:

To see why we need to understand the ACL or Access-control list that is a list of permissions that specify which users can access or modify certain things in a system. Because the source IP doesn't have any parameter and is just a plain IP and packet the Cisco firewall will drop the packet based on the ACL rules, in other words, the Cisco firewall doesn't have any parameter that allows it to verify the permission-level of the sender, therefore, the packet will drop.

7 0

3 years ago

Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number

sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

//Declaration of variables in the program

double start_organisms;

double daily_increase;

int days;

double updated_organisms;

//The user enters the number of organisms as desired

cout << "Enter the starting number of organisms: ";

cin >> start_organisms;

//Validating input data

while (start_organisms < 2)

{

cout << "The starting number of organisms must be at least 2.\n";

cout << "Enter the starting number of organisms: ";

cin >> start_organisms;

}

//The user enters daily input, here's where we apply the 5.2% given in question

cout << "Enter the daily population increase: ";

cin>> daily_increase;

//Validating the increase

while (daily_increase < 0)

{

cout << "The average daily population increase must be a positive value.\n ";

cout << "Enter the daily population increase: ";

cin >> daily_increase;

}

//The user enters number of days

cout << "Enter the number of days: ";

cin >> days;

//Validating the number of days

while (days<1)

{

cout << "The number of days must be at least 1.\n";

cout << "Enter the number of days: ";

cin >> days;

}

//Final calculation and display of results based on formulas

for (int i = 0; i < days; i++)

{

updated_organisms = start_organisms + (daily_increase*start_organisms);

cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

start_organisms = updated_organisms;

}

system("pause");

return 0;

//end

}

Explanation:

6 0

3 years ago

Add the following 2's complement binary numbers. Also express the answer in decimal. a. 01+ 1011b. 11+ 01010101c. 0101+ 110d. 01

kenny6666 [7]

Answer:

(a) 01 + 1011

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 1011

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1 ------------------> + 1 (in decimal)

1 0 1 1 ------------------> - 5 (in decimal)

1 1 0 0 -------------------> - 4 (in decimal)

Explanation for (a)

01 or 0001

Since the most significant bit is 0 (leftmost bit), it shows that it is a positive number. Therefore, it can be directly converted to its decimal representation as follows:

0001 = 0 x $2^{3}$ + 0 x $2^{2}$ + 0 x $2^{1}$ + 1 x $2^{0}$ = 1

0001 is + 1 in decimal.

1011

Its most significant bit(MSB) is 1 showing that it is negative.

Flipping all its bits and adding 1 to the result, will convert it to it's positive counterpart.

i.e 1011 => 0100 + 1 = 0101.

Converting the result (0101) to decimal gives

0101 = 0 x $2^{3}$ + 1 x $2^{2}$ + 0 x $2^{1}$ + 1 x $2^{0}$ = 5

1011 is -5 in decimal

01 + 1011 or 0001+ 1011 = 1100

The result (1100), of the addition of the two numbers, is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1100 => 0011 + 1 = 0100.

Converting the result (0100) to decimal gives

0100 = 0 x $2^{3}$ + 1 x $2^{2}$ + 0 x $2^{1}$ + 0 x $2^{0}$ = 4

Therefore, the result, 1100 is -4 in decimal.

===================================================

(b) 11 + 01010101

Convert the two numbers into their 8-bit representation since one of them is in 8-bit.

PS: Taking 11, its MSB is 1 showing that it is a negative number. Also, it's 8-bit representation will mean pre-padding it with ones(1s) rather than zeros as follows. In other words, pre-padding a 2's complement number is done using its sign bit.

=> 11 = 11111111

=> 01010101

Addition of the two numbers (in their 2's complement form) gives the following:

1 1 1 1 1 1 1 1 ------------------> - 1 (in decimal)

0 1 0 1 0 1 0 1 ------------------> + 85 (in decimal)

1 0 1 0 1 0 1 0 0 -------------------> + 84 (in decimal)

Discard the carry-out bit (1) making the result 01010100

Explanation for (b)

11 or 11111111

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

11111111 => 00000000 + 1 = 00000001

Converting the result (00000001) to decimal gives 1

11 or 11111111 is - 1 in decimal.

01010101

Its MSB is 0 showing that it is also positive. Now, convert to decimal

01010101 = 85

01010101 is + 85 in decimal.

11111111 + 01010101 = 01010100

The result (01010100), is also positive as the MSB is 0. Now, convert to decimal.

01010100 = 84

Therefore the result (01010100) is + 84 in decimal.

===================================================

(c) 0101 + 110

Convert the two numbers into their 4-bit representations.

=> 0101 = 0101

=> 110 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 1 0 1 ------------------> + 5 (in decimal)

1 1 1 0 -----------------> - 2 (in decimal)

1 0 0 1 1 -------------------> + 3 (in decimal)

Dicard the carry-out bit (leftmost bit) to get 0011 as result.

Explanation for (c)

0101

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now, convert to decimal.

0101 = 5

0101 is +5 in decimal.

110 or 1110

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 = 2

1110 is -2 in decimal

0101 + 110 = 0101+ 1110 = 0011

The result (0011), is a positive number as the MSB is 0.

Converting the result (0011) to decimal gives

0011 = 3

Therefore, the result, 0011 is 3 in decimal.

===================================================

(d) 01 + 10

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 10 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1 ------------------> + 1 (in decimal)

1 1 1 0 ------------------> - 2 (in decimal)

1 1 1 1 -------------------> - 1 (in decimal)

Explanation for (d)

01 or 0001

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now convert to decimal.

0001 = 1

0001 is + 1 in decimal.

1110

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 = 2

1110 is -2 in decimal

01 + 1011 or 0001+ 1110 = 1111

The result (1111), is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1111 => 0000 + 1 = 0001.

Converting the result (0001) to decimal gives

0001 = 1

Therefore, the result, 1111 is -1 in decimal.

7 0

4 years ago

10 POINTS! Janis is the only person who can respond to customer inquiries in her small travel company. She receives several cust

Katyanochek1 [597]

The mode of interent she would be using is A. Email. Customer inquires/ Customer Service is normally provided using the mode of Email. Hope it helps!

6 0

3 years ago

Read 2 more answers

What are 3 important reasons to reconcile bank and credit card accounts at set dates?

Karo-lina-s [1.5K]

Answer:

To verify transactions have the correct date assigned to them.

To verify that an account balance is within its credit limit.

To verify that all transactions have been recorded for the period.

Explanation:

7 0

3 years ago