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mafiozo [28]
3 years ago
5

What is the value of x? Enter your answer in the box.

Mathematics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

x = 111°

Step-by-step explanation:

180 x (7 - 1) - (120 + 158 + 126 + 125 + 121 + 139) =

900 - 789 = 111

You might be interested in
What is the sum of the first five terms of a geometric series with a1 =20 and r =1/4?
drek231 [11]
The sum of the first n terms in a geometric sequence given the first term (a1) and the common ratio (r) is calculated through the equation,

                            <span>Sn </span>= (<span><span><span>a1</span>(1−<span>r^n</span>) / (</span><span>1−r)

Substituting the known terms,
                           Sn = (20)(1 - (1/4)^4)) / (1 - 1/4)
                           Sn = 26.5625

Thus, the sum of the first four terms is 26.5625. </span></span>
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%2B1%3D3%5C%5C" id="TexFormula1" title="\sqrt{x} +1=3\\" alt="\sqrt{x} +1=3\\
Eduardwww [97]

Answer:

x = 4

Step-by-step explanation:

√x + 1 = 3

√x = 3 - 1

√x = 2

(√x)² = (2)²

x = 4

4 0
3 years ago
Is 12.56 bigger than 125.6
VARVARA [1.3K]
No it's smaller. 12.56 is much less than 125.6.

5 0
3 years ago
What is slope? Provide two examples of realistic situations where slope manifests itself. In each example make sure to state wha
erastovalidia [21]

Answer:

1. A slope is a surface of which one end or side is at a higher level than another; a rising or falling surface.

"he slithered helplessly down the slope"

Some real life examples of slope include: in building roads one must figure out how steep the road will be. skiers/snowboarders need to consider the slopes of hills in order to judge the dangers, speeds, etc. when constructing wheelchair ramps, slope is a major consideration.

8 0
3 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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