Please Answer this I really need help.<br> 45 points + brainliest.

Write an equation for the line in slope-intercept form, Passing through the point (1,-6) and (-1,0)

Ludmilka [50]

Answer:

y=3x+3

Step-by-step explanation:

y=mx+b is slope intercept form

to find the slope(m) you need to plug your numbers into the equation y(2)-y(1)/x(2)-x(1)

which means subtract the Y's together and the X's together and put the quotient of the Y's on top. Note that you have to choose a set of number to be the first group and the other set as the second group

so (0-6)/(-1-1) = -6/-2 = 3

3 will be your slope. plug that and a set of your numbers into the slope intercept equation

0=3(-1)+b

0=-3+b

3=b

y=3x+3

7 0

3 years ago

A train travels at a constant speed of 35 mi/h.

Setler [38]

It will take the train 14 hours to reach miles,
I got this by dividing 35 by 490.

5 0

3 years ago

Read 2 more answers

The function f(x)=x^2 -6x+3 is transformed such that g(x)=f(x-2). Find the vertex of g(x).

Lisa [10]

Answer:

$g(x) = (x-2)^2 -6(x-2) +3$

$g(x) = x^2 -4x +4 -6x +12 +3$

$g(x) = x^2 -10 x +19$

$g(x) = x^2 -10 x + 25 +19 -25$

$g(x) = (x-5)^2 -6$

$y= (x-h)^2 -kk$

Where h,k represent the vertex and we got:

$(h,k)= (5,6)$

(5,6)

Step-by-step explanation:

We have this original function given :

$f(x) = x^2 -6x +3$

And we want to find the vertex for this new function $g(x) = f(x-2)$ and we have:

$g(x) = (x-2)^2 -6(x-2) +3$

And solving the square we got:

$g(x) = x^2 -4x +4 -6x +12 +3$

And adding similar terms we got:

$g(x) = x^2 -10 x +19$

Now we can complete the square like this:

$g(x) = x^2 -10 x + 25 +19 -25$

$g(x) = (x-5)^2 -6$

The general equation is given by:

$y= (x-h)^2 -kk$

Where h,k represent the vertex and we got:

$(h,k)= (5,6)$

(5,6)

5 0

4 years ago

What is the resulting equation?

nadezda [96]

The answer for this question is B.

3 0

3 years ago

What is 5x+538/23*1000-500=?

Leokris [45]

Answer:

x = (-105300)/23

Step-by-step explanation:

Solve for x:

5 x + 526500/23 = 0

Hint: | Put the fractions in 5 x + 526500/23 over a common denominator.

Put each term in 5 x + 526500/23 over the common denominator 23: 5 x + 526500/23 = (115 x)/23 + 526500/23:

(115 x)/23 + 526500/23 = 0

Hint: | Combine (115 x)/23 + 526500/23 into a single fraction.

(115 x)/23 + 526500/23 = (115 x + 526500)/23:

(115 x + 526500)/23 = 0

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (115 x + 526500)/23 = 0 by 23:

(23 (115 x + 526500))/23 = 23×0

Hint: | Cancel common terms in the numerator and denominator of (23 (115 x + 526500))/23.

(23 (115 x + 526500))/23 = 23/23×(115 x + 526500) = 115 x + 526500:

115 x + 526500 = 23×0

Hint: | Any number times zero is zero.

0×23 = 0:

115 x + 526500 = 0

Hint: | Isolate terms with x to the left hand side.

Subtract 526500 from both sides:

115 x + (526500 - 526500) = -526500

Hint: | Look for the difference of two identical terms.

526500 - 526500 = 0:

115 x = -526500

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 115 x = -526500 by 115:

(115 x)/115 = (-526500)/115

Hint: | Any nonzero number divided by itself is one.

115/115 = 1:

x = (-526500)/115

Hint: | In (-526500)/115, the numbers 526500 in the numerator and 115 in the denominator have gcd greater than one.

The gcd of 526500 and 115 is 5, so (-526500)/115 = (-(5×105300))/(5×23) = 5/5×(-105300)/23 = (-105300)/23:

Answer: x = (-105300)/23

5 0

4 years ago

Please Answer this I really need help. 45 points + brainliest.