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uysha [10]
4 years ago
6

Decide whether or not the ordered pair is a solution of the equation x + y=13;(6,7)

Mathematics
2 answers:
DaniilM [7]4 years ago
7 0

Answer:

yes (6,7) is a solution.

Step-by-step explanation:

(6,7) is an ordered pair, see it like (x,y). so

x=6

y=7

substitute the variable with the values.

x+y=13

6+7=13

13=13

this is a true statement.

e-lub [12.9K]4 years ago
7 0

Answer:

yes

Step-by-step explanation:

To determine if an ordered pair is a solution to an equation.

Substitute the coordinates of the point into the left side and if equal to the right side then the point is a solution, that is

left side = x + y = 6 + 7 = 13 = right side

Hence (6, 7) is a solution to the equation

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Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
While eating dinner, Marian ate 25% of the apple slices she had in her bag. There were 20 apple slices in her bag. How many appl
Kay [80]

Answer:

She ate 5 apple slices

Step-by-step explanation:

25% of 20 is 5.

That means if she ate 5 slices, she ate 25% of the apple slices.

Hope this helped! Please give brainliest if it did help!

3 0
3 years ago
Read 2 more answers
Which is the graph of g(x)=10/x
Elan Coil [88]

Answer:

y=0

Step-by-step explanation:

Find where the expression  

10

x

is undefined.

x

=

0

Consider the rational function  

R

(

x

)

=

a

x

n

b

x

m

where  

n

is the degree of the numerator and  

m

is the degree of the denominator.

1. If  

n

<

m

, then the x-axis,  

y

=

0

, is the horizontal asymptote.

2. If  

n

=

m

, then the horizontal asymptote is the line  

y

=

a

b

.

3. If  

n

>

m

, then there is no horizontal asymptote (there is an oblique asymptote).

Find  

n

and  

m

.

n

=

0

m

=

1

Since  

n

<

m

, the x-axis,  

y

=

0

, is the horizontal asymptote.

y

=

0

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:  

x

=

0

Horizontal Asymptotes:  

y

=

0

No Oblique Asymptotes

image of graph

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Yolanda has $85 but spends $5 a day on Starbucks. How long until she runs out of money?
nata0808 [166]
$85 divided by $5 = 17 days.
8 0
3 years ago
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Let f(x) = 4x2 + 6 and let g(x) = 8x – 6. Find f(g(x)) and g(f(x)).
Artyom0805 [142]

Answer:

f(g (x))= 32x-18

g (f (x))=32x2+42

Step-by-step explanation:

f (g (x))= 4 (8x-6)+6

32x-24-6

32x-18

g (f (x))= 8(4x2+6)-6

32x2+48-6

32x2+42

4 0
3 years ago
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