False because you can subtract your way out of the set of whole numbers
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Let's say the cost of student tickets is x and the cost of adult tickets is y. Then:
(1) 12y + 6x = 138
(2) 5y + 11x = 100
If we rearrange equation (1) we get:
12y = 138 - 6x
Now divide each side by 12:
y = 11.5 - 0.5x
We can now substitute this into equation (2):
5(11.5 - 0.5x) + 11x = 100
57.5 - 2.5x + 11x = 100
8.5x = 42.5
x = 5, therefor the cost of a student ticket is $5.00
Finding two geometric means between 10 and 125:
a 1 = 10, a 4 = 1250
a 4 = a 1 * q^3
1250 = 10 * q^3
q^3 = 1250 : 10
q^3 = 125
q = 5
a 2 = 10 * 5 = 50
a 3 = 10 * 5² = 10 * 25 = 250
Answer: The two geometric means are: 50 and 250, since 10, 50, 250 , 1250 forms a geometric sequence.
Answer:x=31
angle AOC = 124
angle BOC = 56
Step-by-step explanation:
We first need to solve for x to solve the rest. We would normally solve for x by setting 2 equations equal to each other, in this case however, we know that the two angles are adjacent and in total add up to 180. Therefore we combine like terms of both angles, and set them equal to 180.
So, we do
3x+31+2x-6=180 We will combine like terms
5x+25=180 Now we will do inverse operations
5x=155
x=31
We plug x into angle AOC to solve for it
3(31)+31= 124
180-124=56 or angle BOC because the whole angle is 180, and if we subtract 124 from 180 we get the remainder which is angle BOC
Or if you want,
2(31)-6=56
