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Shkiper50 [21]
3 years ago
7

How many centimeters are in six hundred millimeters?

Mathematics
2 answers:
olga55 [171]3 years ago
6 0
60 cm are in 600 mm.
stepan [7]3 years ago
3 0
The answer is 600 cm
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You purchased an investment for $5000 that gains 11% in value every year.
german

Answer:

After 20 years the investment will be worth 11,000$

Step-by-step explanation:

in order to solve the problem you have to turn the percent into a decimal by moving the percent sign twice to the left. which will result in ".11"

then you multiply 5,000x.11 and it equals to 550 per year.

multiply 550x20 and you get 11,000

if I'm not correct please tell me the right answer! goodluck!

3 0
4 years ago
Read 2 more answers
A bag contains red and blue marbles, such that the probability of drawing a blue marble is
ivanzaharov [21]

Answer:

the answer is a 24%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
4 years ago
If M ∠nop = 31 and m ∠NOQ=114 what is m ∠ROQ?
yulyashka [42]

Answer: 83

Step-by-step explanation:

if 31 is m nop and nog is 114 then you subtract 31 from 114

4 0
3 years ago
Would this be 90? with steps please ​
BartSMP [9]

Answer:

K so the added measure of all the angles in a rhombus should be 360 degrees so the answer is 90.

Step-by-step explanation:

i dunno how else to explain.

7 0
3 years ago
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