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3 years ago

How to check your work on a division problem.

Mathematics

2 answers:

Rus_ich [418]3 years ago

4 0

Answer:

By checking it with multiplication

Step-by-step explanation:

You can use multiplication to check your division answer this way.

Do the division problem.

Multiply the quotient times the divisor.

If there is a remainder, add it to the multiplication product.

Compare this answer to the dividend. They should be the same number (630 = 630).

Verizon [17]3 years ago

3 0

Answer:

Do the division problem.

Multiply the quotient times the divisor.

If there is a remainder, add it to the multiplication product.

Compare this answer to the dividend. They should be the same number

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Sveta_85 [38]

Something happened when you copy and pasted the question, was it important to the question?

8 0

3 years ago

Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?

natima [27]

Answer:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

Step-by-step explanation:

The question is poorly formatted. The original question is:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

We have:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

Open bracket

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 8 as 2^3

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 2^3 as 8

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}$

Expand each exponent

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}$

Split

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}$

Factorize

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

4 0

3 years ago

Read 2 more answers

7.65 x 6 <br> HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

DaniilM [7]

Answer:

the answer is 45.9

Step-by-step explanation:

hope this helps :)

can I plz have brainliest

5 0

3 years ago

Which of the following coordinates belong in the box?

Lera25 [3.4K]

Since the distance from the two known coordinates are known, you can find the slope of the line (for lack of a better word) to work backwards. there is a +5 unit gap between -21 and -16, so the next number would be -26. So, without havint to do any more work, the answer is B.

3 0

3 years ago

Read 2 more answers

hjlf

Answer:

1) {0,1,4}

Step-by-step explanation:

(x,y)

domain is x

range is y

so in this case the domain is 0,1,4

6 0

3 years ago