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3 years ago

There are between and languages spoken around the world.

Mathematics

2 answers:

insens350 [35]3 years ago

8 0

There are 6,500 languages spoken in the world

andrew-mc [135]3 years ago

6 0

There is around 6,500 languages around the world

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If you pay for $25.00 for purchase which includes 11% sales tax. how much is the sale tax?

natulia [17]

10% = $25.00 / 10
= $2.50

1% = $25.00 / 100
$0.25

Add them together to get 11%.

$0.25 + $2.50 = $2.75

Please make this the brainiest answer :3.

4 0

3 years ago

Read 2 more answers

The following is a composite figure. Find the TOTAL AREA of

vampirchik [111]

128 inches
for area , you multiply length times height so it’d be 16 x 8 :)

3 0

3 years ago

800.5x(2x20to the 6 power

olasank [31]

Answer:

800.5×(2×20)=32020

Step-by-step explanation:

800.5×40=32020

3 0

3 years ago

Please help with this Calculus questions

Triss [41]

Answer:

$\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du=\frac{193}{100}=1.93$ .

Step-by-step explanation:

To find $\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du$ .

First, calculate the corresponding indefinite integral:

Integrate term by term:

$\int{\left(- \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2\right)d u}} =\int{2 d u} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u}$

Apply the constant rule $\int c\, du = c u$

$\int{2 d u}} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u} = {\left(2 u\right)} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u}$

Apply the constant multiple rule $\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$

$2 u - {\int{\frac{3 u^{9}}{2} d u}} + \int{\frac{2 u^{4}}{5} d u} = 2 u - {\left(\frac{3}{2} \int{u^{9} d u}\right)} + \left(\frac{2}{5} \int{u^{4} d u}\right)$

Apply the power rule $\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$

$2 u - \frac{3}{2} {\int{u^{9} d u}} + \frac{2}{5} {\int{u^{4} d u}}=2 u - \frac{3}{2} {\frac{u^{1 + 9}}{1 + 9}}+ \frac{2}{5}{\frac{u^{1 + 4}}{1 + 4}}$

Therefore,

$\int{\left(- \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2\right)d u} = - \frac{3 u^{10}}{20} + \frac{2 u^{5}}{25} + 2 u = \frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)$

According to the Fundamental Theorem of Calculus, $\int_a^b F(x) dx=f(b)-f(a)$ , so just evaluate the integral at the endpoints, and that's the answer.

$\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=1\right)}=\frac{193}{100}$

$\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=0\right)}=0$

$\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du=\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=1\right)}-\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=0\right)}=\frac{193}{100}$

6 0

2 years ago

9x-7i>3(3x-7u) help pls

Arisa [49]

Answer

Simplifying

9x + -7i = 3(3x + -7u)

Reorder the terms:

-7i + 9x = 3(3x + -7u)

Reorder the terms:

-7i + 9x = 3(-7u + 3x)

-7i + 9x = (-7u * 3 + 3x * 3)

-7i + 9x = (-21u + 9x)

Add '-9x' to each side of the equation.

-7i + 9x + -9x = -21u + 9x + -9x

Combine like terms: 9x + -9x = 0

-7i + 0 = -21u + 9x + -9x

-7i = -21u + 9x + -9x

Combine like terms: 9x + -9x = 0

-7i = -21u + 0

-7i = -21u

Solving

-7i = -21u

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '-7'.

i = 3u

Simplifying

i = 3u

8 0

2 years ago