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3 years ago

Jerry has $558 to spend on dining room chairs. if each chair costs $58, does he have enough to purchase nine chairs

Mathematics

1 answer:

netineya [11]3 years ago

4 0

Answer:

No because the chairs would have to be the price of $62.00

Step-by-step explanation:

divide 558 by 9

so if the chairs had been 62 dollars then he would have enough

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11111nata11111 [884]

What’s the question?

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2 years ago

Write an equation of a line with the given slope and y-intercept

Verizon [17]

Y=mx+b
m=slope
b=yint

given
m=2
b=4/5
easy

y=2x+4/5

A

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3 years ago

A manufacturer of computer logic boards is changing to a new model. The amount of time to setup for the new logic boards is

natima [27]

Answer:

1.5 batches take 12.375 hour

Step-by-step explanation:

The first batch takes 10.5 hours, meaning only .5 batches are left. You then take the time that each new full batch takes (4.25) and divide it by 2 as you only need half of one batch. Meaning 0.5 of a batch takes 2.125 hours. You then take the time of the two batches (10.5, and 2.125) and add them, leaving you with 12.625. Meaning 12.375 is the most viable answer.

4 0

2 years ago

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

7 0

2 years ago

una camisa me costo $10.500, con lo que gaste el 25% de mi dinero ¿cuanto dinero tenia? debe ir desarrollo

evablogger [386]

Answer:

25%------10500

100%------x = 100 * 10500 /25 = 42000

Rta: Tenías 42000

8 0

2 years ago