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d1i1m1o1n [39]
3 years ago
5

A restaurant hires an advertising agency to help them attract new customers. The restaurant has an advertising budget that canno

t exceed $20,000. The advertising agency advises the restaurant to pay a popular radio station $750 each week to air an ad.
aw+b less/greater than c
Mathematics
1 answer:
dlinn [17]3 years ago
6 0
750w+1000 < 20,000

(750$ a week, plus the one time ad cost of 1000$ has the be LESS than the budget of 20,000)
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The three trapezoids have the same base lengths, but different angle measures. Which trapezoid has the greatest area? Explain.
Luden [163]

Steps I took:

I drew out a circle with a radius of 1 and drew a trapezoid inscribed in the top portion of it. I outlined the rectangle within the trapezoid and the two right triangles within it. This allowed me to come to the conclusion, using the pythagorean theorem, that the height of the trapezoid is <span><span>h=<span><span>1−<span><span>x2</span>4</span></span><span>−−−−−</span>√</span></span><span>h=<span>1−<span><span>x2</span>4</span></span></span></span>

The formula for the area of a trapezoid is <span><span>A=<span><span>a+b</span>2</span>(h)</span><span>A=<span><span>a+b</span>2</span>(h)</span></span> I am basically solving for the <span>aa</span> here and so far I have:

<span><span>A=<span><span>x+2</span>2</span>(<span><span>1−<span><span>x2</span>4</span></span><span>−−−−−</span>√</span>)</span><span>A=<span><span>x+2</span>2</span>(<span>1−<span><span>x2</span>4</span></span>)</span></span>

I simplified this in order to be able to easily take the derivative of it as such:

<span><span>A=<span><span>x+2</span>2</span>(<span><span><span>4−<span>x2</span></span>4</span><span>−−−−−−</span>√</span>)</span><span>A=<span><span>x+2</span>2</span>(<span><span>4−<span>x2</span></span>4</span>)</span></span>

<span><span>A=<span><span>x+2</span>2</span>(<span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>2</span>)</span><span>A=<span><span>x+2</span>2</span>(<span><span>4−<span>x2</span></span>2</span>)</span></span>

<span><span>A=(<span>14</span>)(x+2)(<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>)</span><span>A=(<span>14</span>)(x+2)(<span>4−<span>x2</span></span>)</span></span>

Then I took the derivative:

<span><span><span>A′</span>=<span>14</span>[(1)(<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>)+(x+2)((<span>12</span>)(4−<span>x2</span><span>)<span>−1/2</span></span>(−2x)]</span><span><span>A′</span>=<span>14</span>[(1)(<span>4−<span>x2</span></span>)+(x+2)((<span>12</span>)(4−<span>x2</span><span>)<span>−1/2</span></span>(−2x)]</span></span>

This all simplified to:

<span><span><span>A′</span>=<span>14</span>[<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>]</span><span><span>A′</span>=<span>14</span>[<span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>]</span></span>

Next, I set the derivative equal to zero in order to find the maximum point (I know that I can prove that it is actually a max point by taking the second derivative later)

<span><span><span>14</span>[<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>]=0</span><span><span>14</span>[<span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>]=0</span></span><span><span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>=0</span><span><span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>=0</span></span><span><span><span><span>4−<span>x2</span>−2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>=0</span><span><span><span>4−<span>x2</span>−2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>=0</span></span><span><span>4−<span>x2</span>−2<span>x2</span>−4x=0</span><span>4−<span>x2</span>−2<span>x2</span>−4x=0</span></span><span><span>−3<span>x2</span>−4x+4=0</span><span>−3<span>x2</span>−4x+4=0</span></span>

so I got:

<span><span>x=−2orx=<span>23</span></span><span>x=−2orx=<span>23</span></span></span>

<span><span>x=−2</span><span>x=−2</span></span> wouldn't make sense so I chose <span><span>x=<span>23</span></span><span>x=<span>23</span></span></span> and plugged it back into my original formula for the area of this trapezoid but my answer doesn't seem to match any of the multiple choice solutions. Where did I go wrong?

calculus optimization
6 0
3 years ago
Read 2 more answers
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