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Kobotan [32]
3 years ago
9

Help Please this is algebra one!!

Mathematics
1 answer:
Veronika [31]3 years ago
5 0
The answer is B.

The basic plan is c = 20 + 8s ($20 initial cost + $8 each session)
The trial plan is c = 12s ($12 each session)

You need to write a table to determine when the two amounts will equal each other. At month 5 we see that you will end up spending the same amount of money on each plan.

    B   T
------------
1) 28  12
2) 36  24
3) 44  36
4) 52  48
5) 60  60


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Answer:

53$

Step-by-step explanation:

6% of 50 is 3, 50+3=53

6 0
3 years ago
Solve the following systems of equations.<br> 2^(2x+y−1) = 32<br> 4^(x−2y) = 2
Rina8888 [55]

Answer:(x,y)=(2.5,1)

Step-by-step explanation:

Given

2^{2x+y-1}=32

2^{2x+y-1}=2^5

thus on comparing  

2x+y=6------1

4^{x-2y}=2

2^{2(x-2y)}=2

On comparing exponent of 2

x-2y=\frac{1}{2} ------2

we get x=2.5

substitute x in 1

y=1

(x,y)=(2.5,1)

6 0
3 years ago
The table below shows the population of a town over x years. A 2-column table with 5 rows. The first column is labeled years wit
mel-nik [20]

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10,346.0(1.1)^x

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
A college entrance exam company determined that a score of 24 on the mathematics portion of the exam suggests that a student is
seraphim [82]

Answer:

a) The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at  0.01% level of significance

<em>They score is above 24 on the math portion of the​ exam</em>

<em>b) </em>

<u><em>Null Hypothesis</em></u>: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

<u>Alternative Hypothesis: </u>H₁: μ ≠ 24

<u>Step-by-step explanation:</u>

<u><em>Step(i)</em></u>:-

Given random sample 'n' = 250

Given data sample mean x⁻ = 24.5

Standard deviation = 3.3

<u><em>Null Hypothesis</em></u>: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

<u>Alternative Hypothesis: </u>H₁: μ ≠ 24

test statistic

Z = \frac{x^{-} - mean}{\frac{S.D}{\sqrt{n} } }

Z = \frac{24.5 - 24}{\frac{3.3}{\sqrt{250} } } = \frac{0.5}{0.2087} = 2.397

a) 99% or 0.01% level of significance

Level of significance ∝ = 0.01

Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.005} =2.576

The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at  0.01% level of significance

<em>They score is above 24 on the math portion of the​ exam</em>

b) 95% or 0.05% level of significance

Level of significance ∝ = 0.05

Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96

The Z -value 2.397 > 1.96 at 95% or 0.05% level of significance

Null hypothesis is Rejected at  0.05% level of significance

<em>They score is below 24 on the math portion of the​ exam</em>

6 0
3 years ago
Iron Man Training While training for an iron man competition, Tony bikes for 60 miles and runs for 15 miles. If his bikes speed
ivolga24 [154]

Answer:

<u>Tony biked 1 hour 40 minutes and run 3 hours 20 minutes.</u>

Step-by-step explanation:

How long did Tony speed on his bike?

Let s to be Tony's running speed, then 8s is Tony's biking speed

Let's recall that Time = Distance/Speed

Bike time + Running time = 5 hrs

Replacing with the real values, we have:

60/8s + 15/s = 5

8s as Lowest Common Denominator

60 + 8 * 15 = 5 * 8s

60 + 120 = 40s

-40s = -180

s = -180-40

s = 4.5 ⇒ 8s = 36

Tony run at 4.5 mph and biked at 36 mph

Now, we can calculate the time, this way:

Bike time = Bike distance/Bike speed

Replacing with the real values, we have:

Bike time = 60/36

Bike time = 5/3 (Dividing by 12)

5/3 hours * 60 = 100 minutes or 1 hour 40 minutes

Running time = 5 hours - 1 hour 40 minutes = 3 hours 20 minutes

<u>Tony biked 1 hour 40 minutes and run 3 hours 20 minutes.</u>

4 0
3 years ago
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