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tresset_1 [31]
3 years ago
14

HELPPPP what do I do exactly ?

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
8 0

First, you draw a line x = y (so points   1, 1        2, 2   etc.)

Then, you draw a parabola x^2 + 2x + 1 (so points 0, 1    1, 4    -1, 0    -2, 1    -3, 4)

Then you take it all, flip it all around upside down and shove it up your bu.tt.







Hope this helps :)

MAXImum [283]3 years ago
4 0

Answer:


Step-by-step explanation:

Note that the squaring function and the square root function are inverses of one another.  If we make a list of perfect squares, we get {1, 4, 9, 16, 25, ...}.  Then the square roots of these numbers are {1, 2, 3, 4, 5, ... }.

Continue making a table of values to plot.  The first row has x=0, y=0; this reflects that the sqrt of 0 is 0.

Fill the first (x-) column with perfect squares and the second (y-) column with the square roots of these perfect squares:

x   y

0   0

1    1

4    2

9    3

and so on.

Now plot the following on the graph:  (1,1), (4,2), (9,3), ....  

Starting at (0,0) and moving to the right (indicating increases in x), plot these  points.  (You'll soon run out of room.)  Draw a smooth curve from (0,0) to connect these points.  The result is a graph of the square root function.

The domain of this function is "the set of all real numbers ≥0" and the range is the same:  "the set of all real numbers ≥0"

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Step-by-step explanation:

Both terms are of odd degree, so the function is an odd function. It is symmetrical with respect to the origin.

__

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  f(x) = x^(3/5)

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