<h3>
Answer: Choice D</h3>
Explanation:
Any time Alyssa is increasing her speed, the graph will move uphill when going from left to right.
If she slows down, then the graph will move downhill when going left to right.
Always move from left to right when reading a graph because this is how the time axis is set up.
Any flat part represents portions where her speed is constant, i.e. doesn't change.
With all that in mind, the answer is choice D because
- The first portion is going uphill (she's increasing her speed). This portion spans horizontally from 0 seconds to 20 seconds.
- The next portion is her slowing down (the graph is going downhill). This portion spans horizontally from 20 seconds to 30 seconds (so we have a 10 second duration).
- The third portion is where Alyssa is driving at some fixed speed that doesn't change. This portion is 20 seconds long.
- The last portion is Alyssa slowing down and coming to a complete stop. This portion is 5 seconds long.
Let's plug in a few points to see which graph belongs to the function f(x) = 2x^2
Let's say x =0, let's find y!
2(0)^2 = 2(0) = 0
So one point on our line is (0.0)
Just finding this point right here eliminates 3 of the answer choices. Your answer is the graph that goes through the point (0,0)
For your added convenience, I have attached the graph. :)
Hello, all we need to do in this case to subtract the amount of money Bob paid for the suit from the amount of money the suit regularly costs. So:
375,95 - 268,35 = 107,6
Bob saves 107,6$.
Answer:
7.76 minutes
Step-by-step explanation:
The +51 is regardless (being the y intercept) so it does not affect our answer. If the employee has to drive one mile (x=1) it will take 7.76 + 51 min to get there. If they have to drive 0 miles (x=0) it will only take 51 min. This is a difference of 7.76. You really just need to take the slope (I just used this example to make it make more sense) as x is the number of miles the employee has to drive, and therefore that times 7.76 would be how much longer it would take to drive to work.