What you meant must be the adaptive advantage of the frogs' lungs. Frogs are considered as amphibians wherein the have this unique ability to reside either on land or in water. Their specialised lungs could be responsible to these which makes them capable of breathing oxygen in water and land.
A liverwort is a flowerless, spore-producing plant.
Answer:
A). glucose
D). carbon dioxide
E). energy
Explanation:
Aerobic Respiration is characterized as the respiration process(metabolic reaction or breaking down of glucose into energy) that occurs in presence of oxygen while anaerobic respiration takes place in the absence of oxygen. The things that are common in both include glucose, energy, and carbon dioxide. <u>Glucose is broken down in both processes(with or without oxygen) while energy and CO2 are the byproducts/released products of the process</u>. Thus, <u>options A, D, and E</u> are the correct answers.
Answer:
Explanation:
In the body, water moves through semi-permeable membranes of cells and from one compartment of the body to another by a process called osmosis. Osmosis is basically the diffusion of water from regions of higher concentration to regions of lower concentration, along an osmotic gradient across a semi-permeable membrane.
<u>Answer:</u> The final population of Proteus vulgaris after 6 hours is 
<u>Explanation:</u>
We are given:
Proteus vulgaris divides and doubles every 28 minutes
Total time given = 6 hours = 360 min (Conversion factor: 1 hr = 60 min)
Number of times Proteus vulgaris doubles in 6 hours = 
Calculating the number of bacteria after 6 hours under ideal conditions:
We are given:
Initial population = 500 cells
Number of times it doubles = 12.857 times
Final Proteus vulgaris population = 
Hence, the final population of Proteus vulgaris after 6 hours is 