Answer:
Option D, 4,2,1, 3
Explanation:
The mitochondrial respiratory chain (MRC) comprises of four membrane bound complexes and it involves the following steps
a) RC complexes (RCC) I and II reduces the RC’s equivalent where RCCI i.e receives electron from the NADH.
b) These electrons are then transferred to the flavin mononucleotide factor and then passed on to the Fe-S embedded cluster .
c) These electron reduces the coenzyme Q to ubiquinol
d) With in the inner mitochondrial membrane (IMM), protons are trans located from IMM to the intermembrane space (IMS)
e) RC complex II then transfer electron from succinate to the cofactor FAD
f) From FAD proton are transferred to the FeS cluster and on the other hand electron move from QH2 to the RC complex III
g) This RC complex III give its electrons to the cytochrome and they are further passes on to the RC complex IV
h) With four redox centers, the terminal RC complex translocate protein by using energy produced in electron transfer thereby converting oxygen into water.
Hence, the correct option is D
Acid rain is a more serious problem on the East Coast.
Answer:
Black dogs = A_B_
Brown dogs = aaB_
Yellow dogs = A_bb and aabb
Explanation:
In laborador retrievers, pigment color is influenced by two genes. Gene A determines the type of pigment produced and gene B affects whether the pigment gets deposited in the hair shaft. If two heterozygous black laborator retrievers were crossed and offspring were produced in a ratio of 9 black dogs to 3 brown dogs to 4 yellow dogs, what are the genotypes of the offspring?
Gene A determines colored pigment.
Gene B ensures that the colored pigment is deposited.
Two heterozygous black laborador retrievers were crossed.
AaBb x AaBb
Progeny
9 A_B_
3 A_bb
3 aaB_
1 aabb
<em>Since there were 9 black, 3 brown and 4 yellow dogs, the possible genotype of the different colors are: </em>
Black dogs = A_B_
Brown dogs = aaB_
Yellow dogs = A_bb and aabb
Hmmm I think it’s 1 cycles per second
A. A segmented body..............................
