Answer:
z = 36 rolls , probability for getting 7 = 1/6
Step-by-step explanation:
A die has 6 possible outcomes, which sums to 36 for two dice for every value on both dice.
The outcomes for rolling both dice for 36 times gives 6 possible outcomes summing to 7, that is, (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).
There the probability of getting a sum dice of 7 is:
= 6 / 36 = 1/6
Answer:
is the answer your looking for
Step-by-step explanation:
Answer:
Step-by-step explanation:
no x-intercept/zero
Answer:m=p/x - n, n=p/x-m
Step-by-step explanation: I hope this is what you are looking for.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
