Question

Please answer the following questions​

Answer 1

Step-by-step explanation:

sorry I can only explain as there are no labels to each diagram

The first diagram is single and can solved using triangular formular given as 1/2 ×base × height

A = 1/2 × 5 × 12

A = 30cm^2..

as for the second one...it consist of 2 diagrams which will be solved separately before adding ...it can simply be done using Pythagoras theorem..

To get the smaller part ...out tita is 45degrees while our adjacent is 4 and opposite is x we are to find x which is the height...

using SOH CAH TOA...

WE HAVE TAN45= opp/adj

Tan45= x/ 4

Tan 45 =1 ...so

1 = x/ 4

and x= 4 ...

so...having our height as 4 and base as 4 ..

Area of smaller triangle become 1/2 × 4 × 4

A = 8cm^2 ...

......SOLVING FOR THE SECOND DIAGRAM ..

WE HAVE the height as ( dotted spot + undotted spot ) = 4 + 4 = 8cm

and our base can be gotten from

Tan45 = opp / adj

1 = 8/x ..

x = 8cm ....so the base is 8 and the height is 8

..

The Area becomes 1/2 × 8×8 = 32cm ...

Total area becomes 32cm + 8cm = 40cm^2