Answer:
Explanation:
The following program is written in Java and creates the divBySum method using a enhanced for loop. In the picture attached below I have provided an example of the output given if called using the array provided in the question and a divisible parameter of 3.
public static int divBySum(int[] arr, int num) {
int sum = 0;
for (int x : arr) {
if ((x % num) == 0) {
sum += x;
}
}
return sum;
}
Answer:
# sum_them function is defined
def sum_them():
# A sample of a given list is used
given_list = [1, 2, 3, 4, 5, 6, 6, 9, 10]
# The total sum of the element is initialized to 0
total = 0
# for-loop to goes through the list
for element in given_list:
# if the index of element is even
# element to power 2 is added to total
if(given_list.index(element) % 2 == 0):
total += (element ** 2)
else:
# else if index of element is odd
# element to power 3 is added to total
total += (element ** 3)
# The total sum of the element is displayed
print("The total is: ", total)
# The function is called to display the sum
sum_them()
Explanation:
The function is written in Python and it is well commented.
Image of sample list used is attached.
