Answer:
B) The heights of the bear should equal the class frequency.
Step-by-step explanation:
In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.
Answer: is it for math
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm

Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams
Solving the inequality given algebraically, the solution of the inequality for the value of m is:
<u>m < -4 OR m > 3</u>
<em><u>Given the following </u></em><em><u>inequality</u></em><em><u>,</u></em>
<em><u /></em>
or
4m + 3 > 15
Let's solve algebraically for the value of m in both inequality statements given.



Or
4m + 3 > 15
- Subtract 3 from each side
4m + 3 - 3 > 15 - 3
4m > 12

m > 3
Therefore, solving the inequality given algebraically, the solution of the inequality for the value of m is:
<u>m < -4 OR m > 3</u>
<u></u>
<u></u>
Learn more here:
brainly.com/question/24434501