Answer:3
Step-by-step explanation:
Answer: sin
= ±
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A =
& cos a=
,thus we get
sin
=±
∴ sin
=±
= ±
since ,360° <
<450°
,180° <
<225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!
We are to verify the identity:
cos(α-B)-cos(α+B) = 2 sinα sinβ
Left hand side = cos(α - B)-cos(α + B)
= cosα cosβ + sinα sinB - (cosα cosB - sinα sinβ)
= cosα cosβ + sinα sinB - cosα cosB + sinα sinβ)
= sinα sinβ + sinα sinβ
= 2 sinα sinβ
= Right Hand side
Sample space: H1, H2, H3, H4, T1, T2, T3, T4
All outcomes if the card is three: H3, T3
I was unclear about the last two parts of the question.
Answer:
x = 6
y = 24
z = there is no z?
Step-by-step explanation:
All angles of a polygon add up to 360 degrees
The 2 parellel lines on top and bottom mean that there are 2 right angles on the left side
3y + 18 = 90
3y = 72
y = 24
15x + 30 + 10x = 180
25x = 150
x = 6