13 teams of cheerleaders. what is the probability that your team performs first and your friend's team performs second

Identificación de la intención del mensaje o del texto leído

Neko [114]

Answer:

La identificación de la intención del mensaje o del texto leído no es otra cosa que la interpretación del mismo. Es decir, a través de la lectura y la identificación de las diferentes variables comunicativas, el lector realiza un análisis del contenido del texto y lo interpreta, buscando dilucidar la intención que el redactor tuvo al momento de escribir el mensaje o texto en cuestión. La interpretación de textos es fundamental para poder comprender lo que se encuentra redactado, es decir, para poder lograr una total comprensión del texto.

7 0

3 years ago

A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei

ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is $576\ cm^{3}$

Part 2) The total surface area of the paperweight is $400\ cm^{2}$

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the square base

H is the height of the pyramid

$B=8^{2}=64\ cm^{2}$

$H=3\ cm$

substitute

$V=\frac{1}{3}(64)(3)=64\ cm^{3}$

step 2

Find the volume of the cube

The volume of the cube is equal to

$V=b^{3}$

$V=8^{3}=512\ cm^{3}$

step 3

Find the volume of the paperweight

$64\ cm^{3}+512\ cm^{3}=576\ cm^{3}$

Part 2) what is the total surface area of the paperweight?

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

$SA=5b^{2}$

$SA=5(8^{2})=320\ cm^{2}$

step 2

Find the lateral area of the pyramid

$LA=4[\frac{1}{2}bh]$

$LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}$

step 3

Find the total surface area of the paperweight

$320\ cm^{2}+80\ cm^{2}=400\ cm^{2}$

8 0

3 years ago

Sinxcosxtanx=1-cos^2x

ycow [4]

Step-by-step explanation:

$sin x \: cos x \: tanx = 1 - {cos}^{2} x \\ LHS \\= sin x \: cos x \: tanx \\ =sin x \: cos x \: \times \frac{sin x}{cos x} \\ = sin x \: \times \frac{sin x}{1} \\ ={sin}^{2} x \\ = 1 - {cos}^{2} x \\ = RHS \\ \therefore \: sin x \: cos x \: tanx = 1 - {cos}^{2} x \\ Hence \: Proved.$