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Aleksandr-060686 [28]
3 years ago
10

Amelia made a line plot of her scores on 25-point math quizzes. What is the difference between the total of her most frequent nu

mber of points per quiz and the total of her greatest number of points scored per quiz? A. 0 points B. 6 points C. 18 points D. 22 points
Mathematics
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

I think it B.

Step-by-step explanation:

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Divide 8x³- 8x⁴-14x³+14x²-4x+4 by 2x²-4 <br>​
Elanso [62]

Answer:

=14

Step-by-step explanation:

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8 0
2 years ago
What is the solution of RootIndex 3 StartRoot x + 8 EndRoot = negative 4?
erica [24]

Answer: First option.

Step-by-step explanation:

Given the following equation provided in the exercise:

\sqrt[3]{x+8}=-4

You can follow the steps indicated below in order to find the solution of this equation:

1. Cubing both sides of the equation, you get:

(\sqrt[3]{x+8})^3=(-4)^3\\\\x+8=-64

2. Finally you must subtract 8 from both sides of the equation:

x+8-8=-64-8\\\\x=-72

You can notice that this solution matches with the first option.

5 0
4 years ago
Read 2 more answers
A cheesecake recipe says, “Mix 12 oz of cream cheese with 15 oz of
miskamm [114]

Answer:

1.5

Step-by-step explanation:

it is one and one half, in other words.

3 0
3 years ago
A website streams movies and television shows to millions of users. Employees know that the average time a user spends per sessi
oksian1 [2.3K]

Using the Central Limit Theorem, it is found that since the sample size is greater than 30, a normal approximation can be used, hence the test can be made.

<h3>Central Limit Theorem</h3>

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the sampling distribution is also approximately normal, as long as n is at least 30.

In this problem, the distribution of lengths is skewed, however, since the sample size is of 100 greater than 30, a normal approximation can be used, hence the test can be made.

To learn more about the Central Limit Theorem, you can check brainly.com/question/24663213

4 0
2 years ago
Mason asks his friends at school to do his questionnaire. This may not be a good sample to use
Vinvika [58]
Because his friends are not representative. If he would want to receive information about his friends, then this would be a good sample, however, considering that Mason probably wants data that are more representative, it would be better for him to gather info from his school or even wider. This would help him get better data for what he wanted to find information about :)
4 0
3 years ago
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