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3 years ago

2y)(2y + 8) = ? A. 4xy – 16x – 4y2 – 16y B. 4xy + 16x – 4y2 – 16y C. 4xy – 4y2 D. 4xy + 16x + 4y2 + 16y 8…

Mathematics

1 answer:

Vilka [71]3 years ago

8 0

4y^2 + 16y
You distribute the 2y into the 2y+8

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sdas [7]

I can't see the whole problem

3 0

3 years ago

2x - 1 = 17...............

Alika [10]

Answer:

x = 9

Step-by-step explanation:

2x - 1 + 1 = 17 + 1

2x = 18

(2x=18)/2

x = 9

8 0

2 years ago

Read 2 more answers

A researchers wants to determine the mean weight of avocados grown in Southern California. The population from which the sample

natka813 [3]

Answer: (0.465, 5.535)

Step-by-step explanation:

Formula to calculate the confidence interval (<em>when population standard deviation is unknown</em>) is given by :-

$\overline{x}\pm t_{\alpha/2} \dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

s= sample standard deviation.

n= Sample size.

$t_{\alpha/2}$ = critical value

By considering the given information , we have

$\overline{x}=6$

s=0.75

n= 9

Significance level = $\alpha=0.1$ [1-0.90=0.1]

By using students' t distribution -table , the critical value for 95% confidence level :

$t_{\alpha/2 , n-1}=t_{0.1/2,\ 8}=1.86$

[Note: degree of freedom = n-1]

Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :

$6\pm (1.86) \dfrac{0.75}{\sqrt{9}}$

$6\pm (1.86) \dfrac{0.75}{3}$

$6\pm (1.86) 0.25$

$6\pm 0.465=(6-0.465,\ 6+0.465)=(0.465,\ 5.535)$

Hence, the required confidence interval =(0.465, 5.535)

4 0

2 years ago

Dose someone know how to figure this out can someone pleas help its a test

riadik2000 [5.3K]

Complete question is;

The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. In the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

Which equation can be used to find y, the year in which both bodies of water have the same amount of mercury?

A) 0.05 – 0.1y = 0.12 – 0.06y

B) 0.05y + 0.1 = 0.12y + 0.06

C) 0.05 + 0.1y = 0.12 + 0.06y

D) 0.05y – 0.1 = 0.12y – 0.06

Answer:

Option C: 0.05 + 0.1y = 0.12 + 0.06y

Step-by-step explanation:

In the first body, the initial measure of mercury is 0.05 parts per billion (ppb) while it's rising at a rate of 0.1 ppb each year. We are told to use y for the number of years.

Thus, amount of mercury for y years in this first body is;

A1 = 0.05 + 0.1y

Now, for the second body, we are told that;the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

Thus, amount of mercury for y years in this second body is;

A2 = 0.12 + 0.06y

Since we want to find the year in which both bodies of water have the same amount of mercury. Thus, it means;

A1 = A2

Thus;

0.05 + 0.1y = 0.12 + 0.06y

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2 years ago

50 boys and 50 girls with ADD (Attention Deficit Disorder) were selected for an

Vladimir79 [104]

Answer:

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Design of experiments (DOE) is a systematic method to determine the relationship between factors affecting a process and the output of that process. In other words, it is used to find cause-and-effect relationships. ... An understanding of DOE first requires knowledge of some statistical tools and experimentation concepts.

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2 years ago