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Andreyy89
3 years ago
15

Can there be more than one mean or mode in a math problem??

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Math. When no number occurs more than once in a data set, there is no mode. If each of two numbers occurs twice, we say the set is bimodal.
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If 3/4 of the library books are fiction and 5/7 are paperback what fraction of the books are fiction and paperback
Bess [88]

Answer:

15/38

Step-by-step explanation:

assuming the fraction of paperback in the fiction category is also 5/7, the fraction of the books which are fiction and paperback would just be the 2 fractions multiplied together.

3 0
3 years ago
Use properties of operations to complete the equivalent expression. 5(y+9)=​___y+​___ 5(y+9)=nothingy+nothing
laiz [17]

Answer:

5y+45

Step-by-step explanation:

5 0
3 years ago
What is the inverse of the function f(x) = x + 2?
nadya68 [22]

Answer: h(x)=x-2

Step-by-step explanation:

To find the inverse of the function f(x) = x + 2, the first  step is to replace f(x) with "y":

 f(x) =y= x + 2\\\\ y = x + 2

The second step is to solve for the variable "x":

x=y-2

The third step is to interchange the variables, then:

y=x-2

Finally, let be h(x) the inverse of the function f(x). Then, you can replace "y" with h(x). Therefore, this is:

h(x)=x-2

4 0
3 years ago
A young boy let’s out 30 feet of string on his kite. If the angle of elevation from the boy to his kite is 27”, how high is the
const2013 [10]

Answer:

The height of the kite from the ground is 13.617 feet  

Step-by-step explanation:

Given as :

The measure of the string = 30 feet

The angle of elevation from the boy to his kite = 27°

Let the height of the kite from ground = H feet

So, From Triangle

Sin angle = \dfrac{\textrm perpendicular}{\textrm Hypotenuse}

Or, Sin 27° =  \dfrac{\textrm H}{\textrm 30}

or, H = 30 ×  Sin 27°

I.e H = 30 × 0.4539

∴ H = 13.617 feet

Hence the height of the kite from the ground is 13.617 feet   Answer

7 0
2 years ago
What is BE ?<br> Please explain it in full dont just give me an answer
posledela
There are two methods to solve this problem. One of them is the typical method and the other one is the short-cut. I will explain the shortcut

Short-cut: 
This method is quick and easy, and works with ALL triangles, which is why I suggest you use this. You make proportions. Since the triangles are similar, we can use CPCTC. Thereafter,
\frac{AD}{CE}= \frac{DB}{EB}

Now, you just need to identify the terms, substitute, and solve for the unknown, which would be k. 

\frac{12}{3} = \frac{k+5}{k-7} \\ 12(k-7)=3(k+5) \\ 12k-84=3k+15 \\ 9k=84+15 \\ 9k=99 \\ k=11[/tex]

So we found k, but it is asking for BE. Therefore, plug in the value of k, which is 11, into the expression for BE, which is k-7.

BE=K-7
k=11
BE=11-7
BE=4

Your answer is 4.





5 0
3 years ago
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