Please help! Find the domain of y = 4 square root 4x + 2
1 answer:
Answer:
x ≥ -1/2
Step-by-step explanation:
We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:
To find our domain, we need to set the square root equal to zero:
√(4x + 2) = 0
4x + 2 = 0
4x = -2
x = -1/2
We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2
Alternatively, we can graph the function and analyze domain:
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9514 1404 393
Answer:
q = 40
Step-by-step explanation:
When the quadratic has roots p and r, it can be factored as ...
(x -p)(x -r) = x² -(p+r)x +pr
So, the sum of the roots is 14, and their difference is 6. This lets us find the roots from ...
p + r = 14
p - r = 6
2p = 20 . . . add the two equations
p = 10
r = 14 -p = 4
The value of interest is then ...
q = pr = (10)(4)
q = 40
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The graph shows the roots to be 4 and 10, as we found.
Answer:
Step-by-step explanation:
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