-1 is the rest, because its degree is smaller than that of the divisor and therefore can not continue dividing.
x ^ 3 - x ^ 2 + x -1 is the quotient.
I attach the solution
x ^ 3 - x ^ 2 + x -1 is the quotient.
I attach the solution
Please help! Find the domain of y = 4 square root 4x + 2
1 answer:
Answer:
x ≥ -1/2
Step-by-step explanation:
We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:
To find our domain, we need to set the square root equal to zero:
√(4x + 2) = 0
4x + 2 = 0
4x = -2
x = -1/2
We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2
Alternatively, we can graph the function and analyze domain:
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