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Gnom [1K]
3 years ago
7

What is 60 divided by 3 I can't think

Mathematics
2 answers:
Veronika [31]3 years ago
4 0
The answer is 20 lol
hope this helped
Otrada [13]3 years ago
4 0
60 divided by 3 would be 20 You can do 60/3 And to check you can do 20+20+20
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Which equation can be used to solve for the value of n if 2 + n = 12?
In-s [12.5K]
N=12-2 is the answer of this question
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3 years ago
What is the value of x ? (Make sure you give the value of x !!!!)
DochEvi [55]

Answer:

The value of x is 20 degrees.

Step-by-step explanation:

The three angles of a triangle must equal 180 degrees.

100 + 40 + 2x = 140 + 2x

180 - 140 = 40 (goal)

2(x) = 40

2(20) = 40

A) 20 degrees

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2 years ago
Basic Gemoetry Question please help
Oliga [24]

Answer:

D)

Step-by-step explanation:

DE is the radius of both circles

6 0
3 years ago
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
GIVING BRAINLIEST how many O's are in one thousand
Jlenok [28]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
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