To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above: <span>The frequency of A4 is 440.00 Hz.
2. So, you must apply the following formula to calculate the frequency of A6, which is two octaves above:
(2</span>^n)f
Where n is the octaves above and f is the known frequency.
3. Therefore, you have:
A6=(2^n)f
A6=(2^2)(440.00 Hz)
A6=1760 Hz
Therefore, the answer is: A6=1760 Hz.
Area of trapezoid:
A = 1/2(b1+b2)h
where
b1 = 30,
b2 = 28+12 = 40
Triangle FOG
a^2 = c^2 - b^2
a^2 = 13^2 - 12^2
a^2 = 169 - 144
a^2 = 25
a = √25
a = 5
FO = 5 so height h = FO = 5
Now you can find the Area of trapezoid
A = 1/2(b1+b2)h
A = 1/2(30 + 40) (5)
A = 1/2(70)(5)
A = 175
Answer
175 square units
Answer:
z=40 degrees
Step-by-step explanation:
a triangle is 180 degrees
<ACB=50 (180-130=50)
50+90=140
180-140=40
We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem.
We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:
at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8
for the second equation
at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6
we group the points based on their original corresponding t's
(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
Answer:
3m+m^2
Step-by-step explanation:
