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andrey2020 [161]
3 years ago
7

HELP MEMMEMEMEMEM PLZZZZZZZZZZZZZZZ

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

8=g-17

Theres the answer



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Can someone help me write the expression
erica [24]

Answer: 4 1/10g^5+5 1/4

Step-by-step explanation:

8 0
3 years ago
A 10-foot ladder is leaning against a wall. The base of the ladder is 2 feet from the base of the building. How far up the build
Svetlanka [38]
We can see on this graph that the triangle has legs of x and 6 with a hypotenuse of 10 and we can use Pythagoreans theorem to find the unknown side.
Pythagoreans theorem: a^2+b^2=c^2, where a and b are the legs of the triangle and c, is the hypotenuse 

x^2+6^2=10^2 Plugin a=x, b=6, and c=10. Now let us solve for x 

x^2+36=100 Square each individual term 

x^2+=100+36 Subtract 36 from both sides 

x^2=64 Combine like terms 

sqrt(2)=sqrt(64) Take the square root of both sides 

x = 8 Simplify the square root 

So our answer is x = 8 
The ladder touches the 8 feet mark on the wall.
5 0
3 years ago
Given the three points (0,3), (4,15), (5,33), determine the equation of the parabola they represent. State the direction the par
Nonamiya [84]

Answer:

D)The equation is f(x)=3x^2−9x+3, and the parabola opens upward.

3 0
3 years ago
Marquise has 200200200 meters of fencing to build a rectangular garden.
Lera25 [3.4K]

Answer:

2500 Square meters

Step-by-step explanation:

Given the garden area (as a function of its width) as:

A(w)=-w^2+100w

The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.

A'(w)=-2w+100

-2w+100=0

-2w=-100

w=50 meters

Since Marquise has 200 meters of fencing to build a rectangular garden,

Perimeter of the proposed garden=200 meters

Perimeter=2(l+w)

2(l+50)=200

2l+100=200

2l=200-100=100

l=50 meters

The dimensions that will yield the maximum area are therefore:

Length =50 meters

Width=50 meters

Maximum Area Possible =50 X 50 =<u>2500 square meters.</u>

3 0
3 years ago
Multiply and simplify
steposvetlana [31]
That would be the cube root of (x+5)^11.

If desired, this could be reduced to the cube root of (x+5)^9*(x+5)^2, which would be 

(x+5)^3*(x+5)^(2/3)
7 0
3 years ago
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