Answer:
Step-by-step explanation:
Area of a Segment in Radians A = (½) × r2 (θ – Sin θ)
Area of a Segment in Degrees A = (½) × r 2 × [(π/180) θ – sin θ]
Answer:
You would need to use 2.4 cups of sugar if you have 2.5 cups of flour.
Step-by-step explanation:
Divide: 3 divided by 2.5=1.2
Multiply: 1.2 times 2=2.4
Answer: 2.4 cups of sugar
Hope this helped!! :)
Brainliest?!?!
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It takes alvin 20 weeks, and it takes buzzy 15 weeks
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
