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Vladimir79 [104]
3 years ago
6

1/4 divided by 5/6 = 1/a× b/c

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

a= 24b/5c b= 5ac/24 c= 24b/5a

Step-by-step explanation:

Put the problem into a calculator that can solve with variables.

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Based upon past experience, Jessie expects to accidentally overdraft the account about 3 times per year, unfortunately all in th
lorasvet [3.4K]

Answer:

The correct answer is option A.

A. Good Bank will have the least amount in fees per year.

Step-by-step explanation:

Better Bank has a monthly fee of $5 which is lower than Great Bank with a monthly fee of $6, according to the table. Good Bank also allows ATMs to be used twice free of charge, so Jessie would pay only twice a month. These are basically the important features for Jessie, because she won't use checks and other things.

4 0
4 years ago
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Find x if x-l/x-1=-1
shusha [124]

X= X^2  hope it helps :)

8 0
4 years ago
An element with mass 590 grams decays by 19.5% per minute. How much of the
notsponge [240]

22.8 gms

Step-by-step explanation:

Step 1:

Given,

Mass of the element = 590 gms

Percentage decay per minute = 19.5%

Step 2 :

Fraction of the element remaining at the end of 1 minute = 1 - 0.195 = 0.805

Hence the fraction of element remaining after 15 minutes  = 0.805^{15} = 0.03863

So the mass of the element remaining after 15 minutes = 0.03863 * 590 = 22.8 rounded off to the nearest 10th of a gram

mass of the element remaining after 15 minutes = 22.8 gms

6 0
4 years ago
Consider the matrix <img src="https://tex.z-dn.net/?f=A_%7B4x4%7D%2C%20det%28A%29%20%3D%20-2" id="TexFormula1" title="A_{4x4}, d
Lerok [7]

We found a counterexample, so the statement is false.

<h3>Is the statement true?</h3>

Let's use the matrix:

\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]

This is a 4x4 matrix with determinant equal to -2.

The inverse matrix is:

\left[\begin{array}{cccc}1/2&0&0&0\\0&-1&0&0\\0&0&-1&0\\ 0&0&0&-1 \end{array}\right]

If we multiply it by 2, we get:

\left[\begin{array}{cccc}1&0&0&0\\0&-2&0&0\\0&0&-2&0\\ 0&0&0&-2 \end{array}\right]

The adjoint of that is the original matrix, actually:

\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]

Which we already know, has a determinant of -2.

So the statement is false, as we found a counterexample.

If you want to learn more about matrices:

brainly.com/question/11989522

#SPJ1

7 0
2 years ago
On a number​ line, suppose point E has a coordinate of -4 ​, and EG = 13. What are the possible coordinates of point​ G?
Ludmilka [50]

Answer:

9 or -17

Step-by-step explanation:

Hello!

The distance can be positive or negative, as we are just counting the number of units they are apart.

To find the possible coordinates for G, we can add or subtract 13 from -4 to find the possible coordinates for G.

<h3>Find G</h3>
  • -4 + 13 = G1
    -4 - 13 = G2
  • 9 = G1
    -17 = G2

The possible coordinates of G are 9 or -17.

7 0
1 year ago
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