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erastova [34]
3 years ago
8

A company makes uniforms for a fast food restaurant. For every 8 yards of blue fabric, they use 13 yards of white fabric.

Mathematics
1 answer:
zimovet [89]3 years ago
8 0
Since there is no diagram this is how I did it. cross multiply and divide.

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A merchant mixed 8 lb of a cinnamon tea with 6 lb of spice tea. The 14-pound mixture cost $38. A second mixture included 16 lb o
Natasha2012 [34]

Answer:

22

Step-by-step explanation:

5 0
3 years ago
Evie is wrapping a gift. The give is 12 inches long, 4 inches wide, and 6 inches tall. How much wrapping paper will Evie need?
dangina [55]

Answer:

<h2>çevirisi mi lazım sa yazabilirim</h2>
3 0
3 years ago
Read 2 more answers
Solve this system by elimination. <br> 3x+4y=5<br> -5x-4y=-11
ehidna [41]
 3x + 4y = 5
<u>-5x - 4y = -11</u>
       -2x = -6
       -<u>2x</u> = <u>-6</u>
        -2     -2
          x = 3
3(3) + 4y = 5
    9 + 4y = 5
<u>   -9          -9</u>
         4y = -4
         <u>4y</u> = <u>-4</u>
          4      4
           y = -1
     (x, y) = (3, -1)
3 0
3 years ago
Read 2 more answers
Complete the recursive formula of the geometric sequence 500, 200, 80, 32, ....
Ksju [112]

Answer:

times 0.4

Step-by-step explanation:

The recursive formula allows a term in the sequence by multiplying the previous term by the common ratio r

Here

r = \frac{200}{500} = \frac{2}{5} = 0.4

Thus the recursive formula is

c(n) = c(n - 1) × 0.4 → with c(1) = 500 ← the first term in the sequence

8 0
3 years ago
Need help asap. Will mark brainliest.
ZanzabumX [31]

Answer:

X=\begin{bmatrix}17 &3 \\-24  &-12 \\3  &-16 \end{bmatrix}

Step-by-step explanation:

Matrix Equations

Given:

A=\begin{bmatrix}-7 &-2 \\9  &7 \\2  &4 \end{bmatrix}

B=\begin{bmatrix}-4 &-3 \\3  &9 \\9  &-4 \end{bmatrix}

Find X such that:

B - X = 3A

Subtracting B:

- X = 3A - B

Multiplying by -1:

X = -3A + B

Find -3A:

-3A=-3\begin{bmatrix}-7 &-2 \\9  &7 \\2  &4 \end{bmatrix}=\begin{bmatrix}21 &6 \\-27  &-21 \\-6  &-12 \end{bmatrix}

Add to B:

X=-3A+B=\begin{bmatrix}21 &6 \\-27  &-21 \\-6  &-12 \end{bmatrix}+\begin{bmatrix}-4 &-3 \\3  &9 \\9  &-4  \end{bmatrix}=\begin{bmatrix}17 &3 \\-24  &-12 \\3  &-16 \end{bmatrix}

Thus:

X=\begin{bmatrix}17 &3 \\-24  &-12 \\3  &-16 \end{bmatrix}

3 0
3 years ago
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