Multiply 5 by 9.8 to get the answer.
Answer:
Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:
Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:
Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:
Solve for <em>r: </em>
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Simplify. Thus:
Finally, add:
We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:
Answer:
Step-by-step explanation:
To round 4.9 to nearest tenth means to round the numbers so you only have one digit in the fractional part. 4.9 already has only one digit in the fractional part. Thus, 4.9 is already rounded as much as possible to the nearest tenth and the answer is: 4.9
Answer:
They live 285 miles apart
Step-by-step explanation:
Let the total distance be x miles
Sean is driving to visit his friend in another state. In the first hour he travels 1/5 of the total distance. This means that he drove x/5 in the first hour. In the second hour he travels 34 miles. That means
Total distance driven in the first and second hour is
(x/5 + 34)miles
He still has 194 miles more to go.
Therefore,
The total distance is the sum of the distance travelled in the first and second hour + the remaining distance.
x = x/5 + 34 + 194
x = x/5 + 228
Cross multiplying
5x = x + 1140
4x = 1140
x = 1140/4 = 285 miles
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
