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3 years ago

What is The equation of a vertical line passing through the point (-5,-1)

Mathematics

2 answers:

Lana71 [14]3 years ago

8 0

Answer:

The answer is x=-5

Step-by-step explanation:

In order to determine the equation, we need to know about vertical line equations.

In general, a line equation has the form:

$y=mx+n$

Where "y" is the dependent variable, "x" is the independent variable, "m" is the slope of the line and "n" is the value where the line cuts the "y" axis.

A vertical line, x only takes one value. Thus, the equation for a vertical line is x = a, where a is the value that x takes.

So for the coordinate (-5,-1), the vertical line has to pass through the "x" value, that it is -5, therefore the equation of a vertical line passing through the point (-5,-1) is:

x=-5

mihalych1998 [28]3 years ago

3 0

The equation of a vertical line passing through the point (-5,-1) is x = -5

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Y_Kistochka [10]

Answer:

D) y = -1/2x + 4

Step-by-step explanation:

Points on the graph: (0, 4) and (8, 0)

Slope:

m=(y2-y1)/(x2-x1)

m=(0 - 4)/(8-0)

m= -4/8

m = -1/2

Slope-intercept:

y - y1 = m(x - x1)

y - 4 = -1/2(x - 0)

y - 4 = -1/2x

y = -1/2x + 4

8 0

3 years ago

Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma

avanturin [10]

Thanks, this app has helped me a lot.

5 0

3 years ago

Read 2 more answers

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

3 years ago

Please help with this!!! Im so confused, I will mark brainliest if right!! Explain

devlian [24]

Answer: Yes these triangles are similar

Step-by-step explanation:

First lets write down what we know just to make life easier

x=9

TL should be similar to CH

LY should be similar to KH

The angles should be equal due to SAS

So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14

So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14

Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5

Hope this helps.

8 0

3 years ago

4.6.3 Test (CST): Linear Equations

inn [45]

The slope of the green line if the lines are perpendicular is -1/4

<h3>Perpendicular lines</h3>

For two lines two be perpendicular, the product of their slope must be -1. Let the slope of the red and green line be m1 and m2.

Given the following

Slope of red line = 4

According the definition

4m2 = -1

m2 = -1/4

Hence the slope of the green line if the lines are perpendicular is -1/4

Learn more on perpendicular lines here: brainly.com/question/1202004

#SPJ1

5 0

2 years ago