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Andre45 [30]
4 years ago
9

The equation r = 6t gives the number of albums released, r, by a record label over time in years, t. If you graph this relations

hip with time along the x-axis and the number of albums along the y-axis, which points lie on the resulting line?
Mathematics
2 answers:
trapecia [35]4 years ago
7 0

Answer:

The answers are:

           b & e

I took the test I got it right

     Hope this helped :3

                               Megan

svp [43]4 years ago
4 0
Choices:
(7, 44)
(8, 48)
(9, 52)
(12, 74)
<span>(13, 78)

r = 6t 
(7,44) : r = 6(7) = 42 incorrect 
(8,48) : r = 6(8) = 48 CORRECT
(9,52) : r = 6(9) = 54 incorrect
(12,74) : r = 6(12) = 72 incorrect
(13,78) : r = 6(13) = 78 CORRECT

The points that lie on the resulting line are (8,48) and (13,78)</span>
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Answer:

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Step-by-step explanation:

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A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the averag
ahrayia [7]

Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:

X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

8 0
3 years ago
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